Chapter 3.3 Solving Piecewise Rational Inequalities
In this section we will discuss how to solve inequalities involving polynomials.
Polynomial Inequalities
To solve a polynomial inequality of the form \[f(x) > 0,\] write the polynomial in factored form and sketch it.
The \(x\)-values of points on \(f\) that are above the \(x\)-axis are the solutions to the inequality.
Of course, factoring polynomials is a difficult problem. If a polynomial contains a positive irreducible quadratic factor, then this factor does not change the roots or the solutions of the inequality.
In determining solutions to inequalities, such factors may be discarded.
Note: An irreducible quadratic polynomial is a quadratic polynomial that has no real roots. It turns out that any polynomial is a product of linear and irreducible quadratic factors.
Example 1
Find all solutions to the inequalities
- \((x+2)^3(x-2)^2(x-3) > 0\),
- \((x+2)^3(x-2)^2(x-3) \ge 0\),
- \((x+2)^3(x-2)^2(x-3) < 0\),
- \((x+2)^3(x-2)^2(x-3) \leq 0\).
Graph \(f(x)=(x+2)^3(x-2)^2(x-3)\).
- \((-\infty,-2)\cup(3,\infty)\)
- \((-\infty,-2]\cup\{2\}\cup[3,\infty)\)
- \((-2,2)\cup(2,3)\)
- \([-2,3]\)
In this example, we split up the compound inequality to solve this polynomial inequality.
Example 2
Find all solutions to the compound inequality \[2\le x^2-2x+2 < 10.\]
Solve \(2\le x^2-2x+2\) and \(x^2-2x+2<10\).
The inequality \(2\le x^2-2x+2\) is the same as \(0\le x^2-2x\). Factor and graph it to get the solution is \((-\infty,0]\cup[2,\infty)\)]
The inequality \(x^2-2x+2<10\) is the same as \(x^2-2x-8<0\). Factor and graph it to get the solution is \((-2,4)\)
The solution is the intersection of the two solution sets: \((-2,0]\cup[2,4)\).
Inequalities Involving Rational Functions
As with polynomials, sketching a rational function, \(f\), immediately determines the solution sets to the rational inequalities \[f(x) > 0, \quad f(x) \ge 0, \quad f(x) < 0, \quad {\rm and}\quad f(x) \leq 0.\]
We need only observe where \(f\) lies above and below the \(x\)-axis, and where it intersects the \(x\)-axis.
Example 3
Suppose that \[f(x) = \dfrac{(x+3)^2(x+1)(x-3)^5}{x(x-5)^2(x+2)^3}.\] Find all solutions to
- \(f(x) > 0\),
- \(f(x) \ge 0\),
- \(f(x) < 0\),
- \(f(x) \leq 0\).
The graph of \(f(x)\) looks like this
- \((-\infty,-3)\cup(-3,-2)\cup(-1,0)\cup(3,5)\cup(5,\infty)\),
- \((-\infty,-2)\cup[-1,0)\cup[3,5)\cup(5,\infty),\)
- \((-2,-1)\cup(0,3)\),
- \(\{-3\}\cup(-2,-1]\cup(0,3]\).