Chapter 2.8 Practice
\[ \definecolor{ucrblue}{rgb}{0.0627,0.3843,0.6039} \definecolor{ucrgold}{rgb}{0.9686,0.6941,0.2824} \definecolor{ucrred}{rgb}{0.8941,0,0.1686} \definecolor{ucrgreen}{rgb}{0.4706,0.7451,0.1255} \definecolor{ucraccent}{rgb}{1.0000,0.9569,0.8392} \DeclareMathOperator*{\LO}{O} \DeclareMathOperator*{\Lo}{o} \DeclareMathOperator*{\Recip}{Recip} \DeclareMathOperator*{\abs}{abs} \DeclareMathOperator{\pow}{pow} \]
Fully Worked Out Questions
Take \(f\) to be the function that is given by \[f(x) = 2x + 5.\] Find equations for the functions given by \(R(f)\), \(M_y(f)\), and \(M_x(f)\) and sketch \(f\) along with these transformed functions.
Answer
Calculate to get \[R(f)=-\left(2(-x)+5\right)=2x-5,\] \[M_y(f)=2(-x)+5=-2x+5\] \[M_x(f)=-\left(2x+5\right)=-2x-5.\] The sketches of \(f\), \(R(f)\), \(M_y(f)\) and \(M_x(f)\) are shown below:
Sketch the function \(f\), where \[f(x) = \frac{1}{(x+3)}.\] Hint: think of transformations, compare \(f\) to \(g(x)=\frac{1}{x}\).
Answer
The function \(f\) can be rewritten like this: \[f=g\circ T_{3},\] so the sketch of \(f\) looks like this
Sketch the function \(f\), where \[f(x) = \frac{1}{(x-4)^3}.\] Hint: think of transformations, compare \(f\) to \(g(x)=\frac{1}{x^3}\).
Answer
The function \(f\) can be rewritten like this: \[f=g\circ T_{-4},\] so the sketch of \(f\) looks like this
Sketch the function \(f\), where \[f(x) = \frac{1}{(x-3)^4}.\] Hint: think of transformations, compare \(f\) to \(g(x)=\frac{1}{x^4}\).
Answer
The function \(f\) can be rewritten like this: \[f=g\circ T_{3},\] so the sketch of \(f\) looks like this
Define \(\mathrm{Recip}(x)=\frac{1}{x}.\) Use \(y\)-axis inversion to sketch \(\mathrm{Recip}\circ(f)\) where \(f\) is this function:
Answer
The sketch of \(\mathrm{Recip}\circ(f)\) looks like this
Questions
- For each of these functions \(f\), sketch \(f\), determine a formula for \(R(f), M_y(f), M_x(f)\) and sketch these as well.
- \(f(x)=-2x+1\)
- \(f(x)=x^2+1\)
- \(f(x)=|x+2|-1\)
- \(f(x)=\sqrt{x+1}\)
- Define \(\mathrm{Recip}(x)=\frac{1}{x}.\) Use \(y\)-axis inversion to sketch \(\mathrm{Recip}\circ(f)\) where \(f\) is this function:
Answers
- \[R(f)=-2x-1,\] \[M_y(f)=2x+1\] \[M_x(f)=2x-1.\] The sketches of \(f\), \(R(f)\), \(M_y(f)\) and \(M_x(f)\) are shown below:
- \[R(f)=-x^2-1,\] \[M_y(f)1=x^2+1\] \[M_x(f)=-x^2-1.\] The sketches of \(f\), \(R(f)\), \(M_y(f)\) and \(M_x(f)\) are shown below:
- \[R(f)=-|-x+2|+1,\] \[M_y(f)=|-x+2|-1\] \[M_x(f)=-|x+2|+1.\] The sketches of \(f\), \(R(f)\), \(M_y(f)\) and \(M_x(f)\) are shown below:
- \[R(f)=-\sqrt{-x+1},\] \[M_y(f)=\sqrt{-x+1}\] \[M_x(f)=-\sqrt{x+1}.\] The sketches of \(f\), \(R(f)\), \(M_y(f)\) and \(M_x(f)\) are shown below:
- \[R(f)=-2x-1,\] \[M_y(f)=2x+1\] \[M_x(f)=2x-1.\] The sketches of \(f\), \(R(f)\), \(M_y(f)\) and \(M_x(f)\) are shown below: